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NEW QUESTION: 1
Given the code fragment:
Which code fragment, when inserted at line n1, enables the App class to print Equal?
A. Option B
B. Option C
C. Option D
D. Option A
Answer: A
NEW QUESTION: 2
Which of the following statements are true regarding a load balancer? (Choose TWO correct answers.)
A. Failover clusters are not operational without at least one dedicated load balancer.
B. All response packages sent from a backend server to a client must pass through the load balancer.
C. Load balancers may be able to analyze traffic.
D. All incoming connections to the cluster services are received by the load balancer.
E. The load balancer is usually deployed on one of the backend servers.
Answer: C,D
NEW QUESTION: 3
이벤트 그리드를 사용하여 다른 서비스와 연결하는 앱을 만들고 있습니다. 앱의 이벤트 데이터는 규정 준수 여부를 확인하는 서버가 없는 기능으로 전송됩니다. 이 기능은 회사에서 관리합니다.
리소스 범위에서 새 이벤트 구독을 작성합니다. 이벤트는 특정 기간이 지나면 무효화되어야 합니다. 보안을 위해 이벤트 그리드를 구성해야합니다.
무엇을 구현해야 합니까? 대답하려면 [답변 영역]에서 적절한 옵션을 선택하십시오.
참고 : 각각의 올바른 선택은 한 점으로 가치가 있습니다.
Answer:
Explanation:
설명
상자 1 : SAS 토큰
사용자 지정 항목은 SAS (Shared Access Signature) 또는 키 인증을 사용합니다. Microsoft는 SAS를 권장하지만 키 인증은 간단한 프로그래밍을 제공하며 기존의 많은 웹 훅 게시자와 호환됩니다.
이 경우 SAS 토큰이 제공하는 만료 시간이 필요합니다.
박스 2 : ValidationCode 핸드 셰이크
Event Grid는 구독의 유효성을 검사하는 두 가지 방법 인 ValidationCode 핸드 셰이크 (프로그래밍 방식)와 ValidationURL 핸드 셰이크 (수동)를 지원합니다.
끝점의 소스 코드를 제어하는 경우 이 방법을 사용하는 것이 좋습니다.
NEW QUESTION: 4
A. 10.0.0.0/22 is subnetted, 1 subnets D 10.0.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
B. 10.0.0.0/30 is subnetted, 1 subnets D 10.4.4.4 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
C. 10.0.0.0/28 is subnetted, 1 subnets D 10.2.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
D. 10.0.0.0/22 is subnetted, 1 subnets D 10.4.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
E. 10.0.0.0/28 is subnetted, 1 subnets D 10.4.4.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
F. 10.0.0.0/30 is subnetted, 1 subnets D 10.2.2.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
Answer: D
Explanation:
The 10.4.0.0/22 route includes 10.4.0.0/24, 10.4.1.0/24, 10.4.2.0/24 and 10.4.3.0/24 networks only.
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