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Exam Code: 250-585
Exam Name: DX NetOps 23.3.x Technical Specialist
Vendor: Symantec

60 Questions & Answers
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NEW QUESTION: 1
Consider the following user story:
As a customer, I want to the able to cancel an open service request at any time.
Select the configuration option that satisfies the user story.
A. Configure the Cancel button on the user views to resolve the case.
B. Add an alternate stage to the case life cycle.
C. Add a case wide action to the case life cycle.
D. Add a stage-only action to each stage in the case life cycle
Answer: B

NEW QUESTION: 2
Which events will be returned by the following search string?
host=www3 status=503
A. All events that either have a host of www3 or a status of 503.
B. We need more information a search cannot be run without specifying an index
C. All events with a host of www3 that also have a status of 503
D. We need more information: we cannot tell without knowing the time range
Answer: C

NEW QUESTION: 3



A. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.172.23.10, 00:00:16, Serial 1/0
B. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.173.23.10, 00:00:16, FastEthernet 0/0
C. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/13] via 190.172.23.10, 00:00:16, Serial 1/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
D. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
Answer: D
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A
through FastEthernet interface. The interface cost is calculated with the formula 108 /
Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the
cost is 12 (learned from Router_A) + 1 = 13 for both subnets - B is not correct.
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps =
64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link ->
Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 - C &
D are not correct.
In fact, we can quickly eliminate answers B, C and D because they contain at least one
subnet learned from Serial1/0 - they are surely incorrect.


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