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Exam Code: 250-587
Exam Name: Symantec Data Loss Prevention 16.x Administration Technical Specialist
Vendor: Symantec

60 Questions & Answers
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NEW QUESTION: 1
顧客は、業界では、オークションの応答文書はデフォルトのOracle用語「入札」ではなく「提案」と呼ばれ、すべての交渉文書にこの用語を反映させたいと言っています。この要件を満たすために何をしますか?
A. 購買ドキュメントスタイルを作成します。
B. 交渉タイプを作成します。
C. 交渉テンプレートを作成します。
D. 説明フレックスフィールドをカスタマイズします。
E. 交渉スタイルを作成する
Answer: E
Explanation:
交渉スタイルを使用して、ドキュメントの外観と使用可能な機能を制御できます。スタイルは、合理化された交渉を作成するための良い方法です。

NEW QUESTION: 2
Which is part of the Follow-up phase of the Value Engineering Job Plan?
A. Agreeing the implementation plan
B. Presenting recommendations for improving value
C. Monitoring progress of the implementation plan
D. Developing Value Improving Proposals
Answer: C

NEW QUESTION: 3

A. Option E
B. Option D
C. Option C
D. Option B
E. Option A
Answer: A,C,D
Explanation:
E: An execution plan is theresult of the query optimizer's attempt to calculate the most efficient way to implement the request represented by the T-SQL query you submitted. To generate the first execution plan, you can enable the Include Actual Execution Plan option.
B: SET STATISTICS TIME displays the number of milliseconds required to parse, compile, and execute each statement.
C: STATISTICS IO causes SQL Server to display information regarding the amount of disk activity generated by Transact-SQL statements. This is useful information for optimizing queries.
The information include Scan count:
Number of seeks/scans started after reaching the leaf level in any direction to retrieve all the values to construct the final dataset for the output.
Scan count is 0 if the index used is a unique index or clustered index on a primary key and you are seeking for only one value. For example WHERE Primary_Key_Column = <value>.
Scant count is 1 when you are searching for one value using a non-unique clustered index which is defined on anon-primary key column. This is done to check for duplicate values for the keyvalue that you are searching for. For example WHERE Clustered_Index_Key_Column = <value>.
Scan count is N when N is the number of different seek/scan started towards the leftor right side at the leaf level after locating a key value using the index key.

NEW QUESTION: 4
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
SELECT COUNT(*)
A. FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
SELECT COUNT(*)
B. FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(),
112)
SELECT COUNT(*)
D. FROM Purchases
WHERE PurchaseTime = GETDATE()
SELECT COUNT(*)
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
http://technet.microsoft.com/en-us/library/ms181034.aspx


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