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Exam Code: JN0-637
Exam Name: Security, Professional (JNCIP-SEC)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
You are the HR Professional for your organization. You are discussing the status of your company's employees to determine who may be considered nonexempt versus exempt. Which one of the following types of employees can never be considered exempted from overtime provisions?
A. Administrative assistants
B. Managers
C. Sales people
D. Manual workers
Answer: D

NEW QUESTION: 2
You have just graduated from college,now you are serving the internship as the software developer in an international company. There's a Web site that is deployed on a staging server. A test team plans to test performance on a Web site. The test team needs to modify the deployed Web Forms to test different scenarios. You have to deploy the Web site to the staging server without the Web site's source code files. What should you do?
A. You should choose Build Solution to compile the Web site in Microsoft Visual Studio 2005.
B. You should use the Copy Web tool.
C. You should use the Publish Web tool and choose Allow this precompiled site to be updateable.
D. You should use aspnet_compiler.exe with the default options.
Answer: C

NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2012-Server gehostet wird.
Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern.
Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (OrderAmount) DESC) AS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
COUNT (OrderAmount) DESC) ALS OrderAmount
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
BESTELLEN NACH OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (o.OrderAmount) ASC) AS Rnk
VOM KUNDEN c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WO Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
BESTELLUNG NACH BESTELLBETRAG DESC) ALS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
Answer: A


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