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NEW QUESTION: 1
Select two statements that correctly describe the capabilities of the Distribution Constructor.
A. A single Installation server can be used to create ISO images for Solaris 10 and Solaris11 operating systems.
B. ISO images for use with the Automated Installer (AI) can be created.
C. A single installation server can be used to create ISO images for SPARC and x86 architectures.
D. Checkpoints can be used to pause the build, allowing scripts to run that modify the resulting ISO Image.
E. Bootable USB images can be created for SPARC and x86 architectures.
Answer: B,D
Explanation:
Explanation/Reference:
Explanation:
A: You can use the distribution constructor to create the following types of Oracle Solaris images:
* (A) x86 or SPARC ISO Image for Automated Installations
* Oracle Solaris x86 live CD image
* x86 or SPARC Oracle Solaris text installer image
* x86 Oracle Solaris Virtual Machine
Note: You can use the distribution constructor to build custom Oracle Solaris images. Then, you can use the images to install the Oracle Solaris software on individual systems or multiple systems. You can, also, use the distribution constructor to create Virtual Machine (VM) images that run the Oracle Solaris operating system.
D: Checkpointing Options
You can use the options provided in the distro_const command to stop and restart the build process at various stages in the image-generation process, in order to check and debug the image that is being built.
This process of stopping and restarting during the build process is called checkpointing.
NEW QUESTION: 2
Answer:
Explanation:
See explanation
Explanation
Router>enable Router#config terminal Router(config)#hostname Gotha
2) Enable-secret password (cisco10):
Gotha(config)#enable secret mi222ke
3) Set the console password to G8tors1:
Gotha(config)#line console 0 Gotha(config-line)#password G8tors1 Gotha(config-line)#login Gotha(config-line)#exit
4) Set the Telnet password to dun63lap:
Gotha(config)#line vty 0 4 Gotha(config-line)#password dun63lap Gotha(config-line)#login Gotha(config-line)#exit
5) Configure Ethernet interface (on the right) of router Gotha: Ethernet network 209.165.201.0 /27 - Router has the fourth assignable host address in subnet. Ethernet Interface on router R2 is Fast Ethernet 0/0 as per the exhibit First we need to identify the subnet mask Network: 209.165.201.0 /27 Subnet mask: /27: 27 bits = 8 + 8 + 8 + 3 =8(bits).8(bits).8(bits) .11100000 (3bits) =255.255.255.11100000 =11100000 = 128+64+32+0+0+0+0+0 = 224 Subnet mask: 255.255.255.224 Different subnet networks and there valid first and last assignable host address range for above subnet mask are Subnet Networks :::::: Valid Host address range :::::: Broadcast address
209.165.201.0 :::::: 209.165.201.1 - 209.165.201.30 ::::: 209.165.201.31
209.165.201.32 :::::: 209.165.201.33 - 209.165.201.62 ::::: 209.165.201.63
209.165.201.64 :::::: 209.165.201.65 - 209.165.201.94 :::::: 209.165.201.95
209.165.201.96 :::::: 209.165.201.97 - 209.165.201.126 :::::: 209.165.201.127
209.165.201.128 :::::: 209.165.201.129 - 209.165.201.158 :::::: 209.165.201.159
209.165.201.160 :::::: 209.165.201.161 - 209.165.201.190 :::::: 209.165.201.191
209.165.201.192 :::::: 209.165.201.193 - 209.165.201.222 :::::: 209.165.201.223
209. 165.201.224 :::::: 209.165.201.225 - 209.165.201.254 :::::: 209.165.201.255 Use above table information for network 209.165.201.0 /27 to identify First assignable host address: 209.165.201.1 Last assignable host address: 209.165.201.30 Fourth assignable host address: 209.165.201.4 Assign the fourth assignable host address to Fa0/0 interface of Gotha router:
Gotha(config)#interface Fa0/0 Gotha(config-if)#ip address 209.165.201.4 255.255.255.224 Gotha(config-if)#no shutdown Gotha(config-if)#exit
6) Configure Serial interface (on the left) of router Gotha: Serial Network is 192.0.2.176 /28 - Router has the last assignable host address in subnet. Serial Interface on R2 is Serial 0/0/0 as per the exhibit First we need to identify the subnet mask Network: 192.0.2.176 /28 Subnet mask: /28: 28bits = 8bits+8bits+8bits+4bits
=8(bits).8(bits).8(bits) .11110000 (4bits) =255.255.255.11100000 =11100000 = 128+64+32+16+0+0+0+0
240 Subnet mask: 255.255.255.240 Different subnet networks and there valid first and last assignable host address range for above subnet mask are Subnet Networks ::::: Valid Host address ::::::::::: Broadcast address
192.0.2.0 :::::: 192.0.2.1 - 192.0.2.14 ::::::: 192.0.2.15
192.0.2.16 ::::::: 192.0.2.17 - 192.0.2.30 ::::::: 192.0.2.31
192.0.2.32 :::::::: 192.0.2.33 - 192.0.2.46 :::::: 192.0.2.47
192.0.2.48 :::::: 192.0.2.49 - 192.0.2.62 ::::::: 192.0.2.64
192.0.2.64 ::::::: 192.0.2.65 - 192.0.2.78 ::::::: 192.0.2.79
192.0.2.80 :::::::: 192.0.2.81 - 192.0.2.94 :::::: 192.0.2.95
192.0.2.96 :::::: 192.0.2.97 - 192.0.2.110 ::::::: 192.0.2.111
192.0.2.112 ::::::: 192.0.2.113 - 192.0.2.126 ::::::: 192.0.2.127
192.0.2.128 :::::::: 192.0.2.129 - 192.0.2.142 :::::: 192.0.2.143
192.0.2.144 :::::: 192.0.2.145 - 192.0.2.158 ::::::: 192.0.2.159
192.0.2.160 ::::::: 192.0.2.161 - 192.0.2.174 ::::::: 192.0.2.175
192. 0.2.176 :::::::: 192.0.2.177 - 192.0.2.190 :::::: 192.0.2.191 and so on .... Use above table information for network 192.0.2.176 /28 to identify First assignable host address: 192.0.2.177 Last assignable host address:
192.0.2.190
We need to configure Last assignable host address (192.0.2.190) on serial 0/0/0 using the subnet mask
255.255.255.240 Assign the last assignable host address to S0/0/0 interface of Gotha router:
Gotha(config)#interface S0/0/0 (or use interface S0/0 if not successful) Gotha(config-if)#ip address 192.0.2.190 255.255.255.240 Gotha(config-if)#no shutdown Gotha(config-if)#exit
7) Configure RIP v2 routing protocol:
Gotha(config)#router rip Gotha(config-router)#version 2 Gotha(config-router)#network 209.165.201.0 Gotha (config-router)#network 192.0.2.176 Gotha(config-router)#end Save the configuration: Gotha#copy running-config startup-config Finally, you should use the ping command to verify all are working properly!
NEW QUESTION: 3
A. Option C
B. Option A
C. Option B
D. Option D
Answer: C
Explanation:
https://blogs.msdn.microsoft.com/buckwoody/2013/01/08/microsoft-windows-azure- disaster-recovery-options-for-on-premises-sql-server/
NEW QUESTION: 4
A. Option C
B. Option A
C. Option E
D. Option B
E. Option D
Answer: C
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