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    NEW QUESTION: 1
    An ELB is diverting traffic across 5 instances. One of the instances was unhealthy only for 20 minutes.
    What will happen after 20 minutes when the instance becomes healthy?
    A. ELB terminates the instance once it is unhealthy. Thus, the instance cannot be healthy after 10 minutes
    B. ELB will never divert traffic back to the same instance
    C. ELB will not automatically send traffic to the same instance. However, the user can configure to start sending traffic to the same instance
    D. ELB starts sending traffic to the instance once it is healthy
    Answer: D
    Explanation:
    AWS Elastic Load Balancing continuously checks the health of an instance. If one of the instances is unhealthy it stops sending traffic to it and automatically reroutes the traffic to the remaining running EC2 instances. If the failed EC2 instance is restored, Elastic Load Balancing will again start sending traffic to that instance.
    Reference: http://docs.aws.amazon.com/ElasticLoadBalancing/latest/DeveloperGuide/SvcIntro.html

    NEW QUESTION: 2
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    What should the agile practitioner do?
    A. Assign more resources to story B to bring it in line with the estimate
    B. Reestimate all stories including values for A B and C
    C. Add points to story B's iteration to account for the error but keep story B at 3 points
    D. Assign story B more than 8 story points so to provide a better estimate
    Answer: B

    NEW QUESTION: 3
    The network administrator is asked to configure 113 point-to-point links.
    Which IP addressing scheme defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses?
    A. 10.10.0.0/23 subnetted with mask 255.255.255.252
    B. 10.10.1.0/25 subnetted with mask 255.255.255.252
    C. 10.10.0.0/18 subnetted with mask 255.255.255.252
    D. 10.10.1.0/24 subnetted with mask 255.255.255.252
    E. 10.10.0.0/16 subnetted with mask 255.255.255.252
    Answer: A
    Explanation:
    We need 113 point-to-point links which equal to 113 sub-networks < 128 so we need to
    borrow 7 bits (because 2

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    7 = 128).
    The network used for point-to-point connection should be /30.
    So our initial network should be 30 - 7 = 23.
    So 10.10.0.0/23 is the correct answer.
    You can understand it more clearly when writing it in binary form:
    /23 = 1111 1111.1111 1110.0000 0000
    /30 = 1111 1111.1111 1111.1111 1100 (borrow 7 bits)