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Exam Code: 2V0-12.24
Exam Name: VMware vSphere Foundation 5.2 Administrator
Vendor: VMware

60 Questions & Answers
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NEW QUESTION: 1
What Mule application deployment scenario requires using Anypoint Platform Private Cloud Edition or Anypoint Platform for Pivotal Cloud Foundry?
A. When it is required that ALL APIs are private and NOT exposed to the public cloud
B. When ALL backend systems in the application network are deployed in the organization's intranet
C. When regulatory requirements mandate on-premises processing of EVERY data item, including meta-data
D. When it Is required to make ALL applications highly available across multiple data centers
Answer: C

NEW QUESTION: 2
ネットワークには、adatum.comという名前のActive Directoryドメインが含まれています。
ドメインには、Windows Server 2016を実行するServer1という名前のサーバーが含まれています。ドメインには、User1とUser2という名前の2人のユーザーが含まれています。
Server1で、C:Folder1という名前のフォルダーにFile1.docとFile2.docという名前の2つのファイルを作成します。
File1.docの監査項目は、File1展示に示すように構成されています。 (File1タブをクリックしてください。)

File2.docには空の監査エントリリストがあります。
Server1に適用されるグローバルファイルSACLの監査エントリは、SACLの図に示すように構成されています。
(SACLタブをクリックしてください。)

Server1のAdvanced Audit Policy Configurationは、Audit Policyの図に示すように構成されています。
([監査ポリシー]タブをクリックします。)

以下の各ステートメントについて、そのステートメントが正しい場合は「はい」を選択してください。 そうでなければ、いいえを選択します。
注:それぞれ正しい選択は1ポイントの価値があります。

Answer:
Explanation:
Explanation

References:
http://sourcedaddy.com/windows-7/auditing-file-and-folder-access.html

NEW QUESTION: 3
The Ethernet networks connected to router R1 in the graphic have been summarized for router R2 as 192.1.144.0/20. Which of the following packet destination addresses will R2 forward to R1, according to this summary? (Choose two.)

A. 192.1.159.2
B. 192.1.1.144
C. 192.1.143.145
D. 192.1.138.41
E. 192.1.151.254
F. 192.1.160.11
Answer: A,E
Explanation:
This question is about route summary. Example of route summary calculation The routing table stores the following networks: 172.16.12.0/24 172.16.13.0/24 172.16.14.0/24 172.16.15.0/24
Routing protocols summarize or aggregate routes based on shared network numbers within the
network. To calculate the summarized route of the router, it is necessary to determine how many
bits on the left of those addresses are the same. The steps are shown below:
Step onE. Convert addresses to binary format and align them.
Step two: Find out the identical last bit of all addresses.
Step threE. Calculate how many bits are the same. The summarized route is an IP address with a
slash, which will be helpful.
172.16.12.0/24= 172.16.000011 00.00000000
172.16.13.0/24= 172.16.000011 01.00000000
172.16.14.0/24= 172.16.000011 10.00000000
172.16.15.0/24= 172.16.000011 11.00000000
172.16.15.255/24= 172.16.000011 11.11111111
The first 22 bits of IP addresses 172.16.12.0---172.16.15.255 are identical, so the best
summarized route is 172.16.12.0/22.
Using route summary can reduce the routing items on the summarized router to decrease the
memory occupied and network traffic generated by routing protocol.
Route summary implementation:
A. The bits on the left of multiple addresses must be identical.
B. Routing protocol should select route according to the 32-bit IP address and the prefix length of the maximum 32 bit address.
C. Routing update must contain 32-bit IP address and the prefix length (subnet mask)

NEW QUESTION: 4

A. Destination
B. Format
C. TopicAm
D. Subject
E. Message
F. Language
Answer: A,D,E


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