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Exam Code: PK0-004
Exam Name: CompTIA Project+ Certification Exam
Vendor: CompTIA

60 Questions & Answers
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NEW QUESTION: 1
Consider the following process flow:

Decision "A" properties are:

Decision "B" properties are:

Decision "C" properties are:

What will happen when the process runs?
A. The flow will pass through calculation stage "A"
B. The flow will pass through calculation stage "B"
C. The flow will pass through calculation stage "C"
D. An exception will be thrown
Answer: B

NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
C. CustNo IS NULL
D. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
G. CustNo
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
I. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
J. SELECT COUNT (DISTINCT CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
K. CustNo = L.CustNo
Answer: I
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 3
대인 갈등 해결과 관련하여 다음 중 옳은 것은 무엇입니까?
A. 역할과 책임을 시기 적절하고 모호하지 않게 명확히 하면 대부분의 대인 관계 갈등이 제거됩니다.
B. 개편은 아마도 모호하거나 중복되는 관할 구역에 도움이되지 않을 것입니다.
C. 문제를 완전히 처리 할 충분한 시간이 있을 때까지 연기 조치를 사용해야 합니다.
D. 공개적이고 정직한 토론을 통해 실현되지 않은 기대를 피할 수 있습니다.
Answer: D


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