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NEW QUESTION: 1
A client STA must choose the best AP for connectivity. As part of the evaluation, it must verify compatible data rates. What can the client STA use to verify that an AP supports the same data rates that it supports?
A. Authentication frames transmitted by the other client STAs
B. Beacon frames transmitted by the AP
C. Probe request frames transmitted by other client STAs
D. Data frames sent between the AP and current clients STAs
Answer: C
Explanation:
Explanation/Reference:
Reference https://supportforums.cisco.com/t5/wireless-mobility-documents/802-11-sniffer-capture- analysis-management-frames-and-open-auth/ta-p/3120622

NEW QUESTION: 2
残高監査証跡を実行すると、どのような情報が得られますか？正解を選択してください。
A. 顧客口座とサプライヤー口座の未決済口座残高
B. 元帳間の総勘定元帳勘定残高の比較
C. 総勘定元帳勘定の更新済機密項目の変更一覧
D. 開始残高と総勘定元帳の残高の年間変更
Answer: D

NEW QUESTION: 3
The following ban list entry is displayed through the CLI.

Based on this command output, which of the following statements is correct?
A. This diagnostic entry results from the administrator running the diag ips log test command. This command has no effect on traffic.
B. A DLP rule has been matched.
C. The administrator has specified the Attack and Victim Address method for the quarantine.
D. An attack has been repeated more than once during the holddown period; the expiry time has been reset to indefinite.
Answer: C

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
* Students must be ranked based on their average marks.
* If one or more students have the same average, the same rank must be given to these students.
* Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms189798.aspx

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