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Exam Code: JN0-335
Exam Name: Security, Specialist (JNCIS-SEC)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
Which functionality doesWebCenter SitesPublishing use to ensure thatthere are no broken linksorcontent?
A. It copies asset information without the need for SQL queries to the publishing destination.
B. It evaluates asset dependencies before publishing.
C. It can obtain workflow approval automatically prior to publishing.
D. It publishes code as well as content.
Answer: B

NEW QUESTION: 2
Siehe Ausstellung.

Ein Techniker hat die Aufgabe, die Netzwerkkonfigurationsparameter auf einer Client-Workstation zu überprüfen, um dem Teamleiter Bericht zu erstatten. Ziehen Sie die Knotenkennungen von links auf die Netzwerkparameter rechts.

Answer:
Explanation:




NEW QUESTION: 3
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 4 kHz x 8-bit code words
B. 2 x 4-bit code words x 8 kHz
C. 8 kHz x 8-bit code words
D. 2 x 8 kHz x 4-bit code words
Answer: A
Explanation:
Explanation/Reference:
Explanation: While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses
sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400
Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and
sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency
sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz.
According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the
unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per
second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must
be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original
perfectly from the sampled version."

NEW QUESTION: 4
If there is a firewall between Cisco ISE and an Active Directory external identity store, which port does not need to be open?
A. TCP 445
B. TCP 88
C. TCP 21
D. UDP/TCP 389
E. UDP123
Answer: C


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