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Exam Code: JN0-663
Exam Name: Service Provider Routing and Switching, Professional (JNCIP-SP)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
A 67-year-old female presents to your clinic complaining of fatigue, diarrhea, headaches and a loss of appetite.
Upon examination you find that she is having some cognitive difficulty. Laboratory results reveal: MCV:
109fL; Hgb: 9g/dL; MMA and homocystine are both elevated. Shilling test is positive.
What is the next best step in the management of this patient?
A. Give corticosteroids and iron supplementation
B. Obtain a Coomb's test
C. Lifelong Vitamin B12 supplementation
D. Iron supplementation for 4-6 months
E. Lifelong folic acid supplementation
Answer: C
Explanation:
Explanation
Lifelong Vitamin B12 supplementation. Vitamin B12 (cyanocobalamin) deficiency generally presents in patients as fatigue, diarrhea and headaches but can also be the cause of cognitive changes (difficulty concentrating, even mild dementia). Pernicious anemia is a macrocytic anemia, therefore laboratory findings indicate an increased mean corpuscular volume (MCV), with a decreased hemoglobin. A positive Schilling test indicates that the B12 deficiency is due to a lack of intrinsic factor. Lifelong cyanocobalamin supplementation (either orally or via injections) is needed to treat pernicious anemia. A is incorrect. Folic acid deficiency anemia is another common type of macrocytic anemia. However, cognitive deficits are not typically seen with folic acid deficiency. Furthermore, a schilling test would be negative and the methylmalonic acid (MMA) would be normal, rather than elevated. C is incorrect. Iron deficiency anemia causes a microcytic anemia, characterized by a decreased MCV. D is incorrect. A Coomb's test is used to detect autoimmune hemolysis that may be suspected in patients with normocytic anemia (anemia with an MCV in the normal range). E is incorrect. Corticosteroids and iron supplementation are indicated as treatment in hemolytic anemia.

NEW QUESTION: 2
Identify three profile options that are used to configure to Self Service procurement.
A. PO_PRC_AGENT_CATEGORY_ASSIGNMENT
B. POR_DISPLAY_EMBEDDED_ANALYTICS
C. POR_SEARCH_RESU LTS_ SKIN
D. POR_DISPLAY_CATEGORY_ITEM_COUNT
E. PO_DOC_ BUILDER_DEFAULT_DOC_TYPE
Answer: C,D

NEW QUESTION: 3
View the Exhibit and examine the structure of the SALES table.
The following query is written to retrieve all those product IDs from the SALES table that have more than
55000 sold and have been ordered more than 10 times.

Which statement is true regarding this SQL statement?

A. It executes successfully and generates the required result.
B. It produces an error because COUNT(*) should be only in the HAVING clause and not in the WHERE clause.
C. It executes successfully but produces no result because COUNT(prod_id) should be used instead of COUNT(*).
D. It produces an error because COUNT(*) should be specified in the SELECT clause also.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Restricting Group Results with the HAVING Clause
You use the HAVING clause to specify the groups that are to be displayed, thus further restricting the groups on the basis of aggregate information.
In the syntax, group_condition restricts the groups of rows returned to those groups for which the specified condition is true.
The Oracle server performs the following steps when you use the HAVING clause:
1. Rows are grouped.
2. The group function is applied to the group.
3. The groups that match the criteria in the HAVING clause are displayed.
The HAVING clause can precede the GROUP BY clause, but it is recommended that you place the GROUP BY clause first because it is more logical. Groups are formed and group functions are calculated before the HAVING clause is applied to the groups in the SELECT list.
Note: The WHERE clause restricts rows, whereas the HAVING clause restricts groups.

NEW QUESTION: 4
You administer a Microsoft SQL Server 2012 database. The database contains a table named Employee.
Part of the Employee table is shown in the exhibit. (Click the Exhibit button.)


Unless stated above, no columns in the Employee table reference other tables.
Confidential information about the employees is stored in a separate table named EmployeeData. One record exists within EmployeeData for each record in the Employee table.
You need to assign the appropriate constraints and table properties to ensure data integrity and visibility.
On which column in the Employee table should you create a Foreign Key constraint that references a different table in the database?
A. JobTitle
B. MiddleName
C. DepartmentID
D. ReportsToID
E. FirstName
F. EmployeeNum
G. DateHired
H. LastName
I. EmployeeID
Answer: I
Explanation:
Use the EmployeeID, which would be used as a primary key in the Employee table, when defining a foreign key constraint from another table in the database.


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