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Exam Code: FC0-U71
Exam Name: CompTIA Tech+ Certification Exam
Vendor: CompTIA

60 Questions & Answers
Verified by IT Certification Professionals

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NEW QUESTION: 1
An Apex Sharing Reason cannot be created on a custom object with the label 'Manual Sharing' because the in-built standard sharing reason provided by Salesforce has the same label, so it would give error
"An Apex Sharing Reason with this name already exists"
A. False
B. True
Answer: A

NEW QUESTION: 2
On a network with multiple VLANs, which three tasks must you perform to configure IP source guard on VLAN 50 only?(choose three)
A. Configure the ip dhcp snooping command global
B. Configure the ip verify source command on the interface
C. Configure the ip dhcp snooping command on the interface
D. Configure the ip verify source command globally
E. Configure the ip dhcp snooping vlan 50 command globally
F. Configure the ip dhcp snooping vlan 50 command on the interface
Answer: A,B,E

NEW QUESTION: 3
Given:

What is the result?
A. true . . \ . . \ . . \ annualreport.txt
B. false \sales\quarter\ . . \qtrlreport.txt
C. true \ . . \ . . \annualreport.txt
D. false \quarter\ . . \qtrlreport.txt
Answer: B
Explanation:
( richtig !! import java.nio.file.Path; import java.nio.file.Paths; ) original-Aufgabe war ( falsch >>
import java.io.file.Path; import java.io.file.Paths; )
The relativize method that can be used to construct a relative path between two paths.
relativize
Path relativize(Path other)
Constructs a relative path between this path and a given path.
Parameters: other - the path to relativize against this path
Returns: the resulting relative path, or an empty path if both paths are equal
Note:
Relativization is the inverse of resolution. This method attempts to construct a relative path that when resolved against this path, yields a path that locates the same file as the given path. For 18 example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the resulting relative path would be "c/d". Where this path and the given path do not have a root component, then a relative path can be constructed. A relative path cannot be constructed if only one of the paths have a root component. Where both paths have a root component then it is implementation dependent if a relative path can be constructed. If this path and the given path are equal then an empty path is returned.
For any two normalized paths p and q, where q does not have a root component, p.relativize(p.resolve(q)).equals(q)
When symbolic links are supported, then whether the resulting path, when resolved against this path, yields a path that can be used to locate the same file as other is implementation dependent. For example, if this path is "/a/b" and the given path is "/a/x" then the resulting relative path may be "../x". If "b" is a symbolic link then is implementation dependent if "a/b/../x" would locate the same file as "/a/x".


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