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NEW QUESTION: 1
Refer to the exhibit. In this network, R1 has been configured to advertise a summary route, 192.168.0.0/22, to R2. R2 has been configured to advertise a summary route, 192.168.0.0/21, to R1. Both routers have been configured to remove the discard route (the route to null created when a summary route is configured) by setting the administrative distance of the discard route to 255. What will happen if R1 receives a packet destined to
192.168.3.1 ?
A. The packet will loop between R1 and R2.
B. The packet will be dropped by R1, since there is no route to 192.168.3.1.
C. It is not possible to set the administrative distance on a summary to 255.
D. The packet will be forwarded to R2, where it will be routed to null0.
Answer: A
Explanation:
Indeed, when you change the administrative distance of the discard route to 255, this
prevents the route to be installed in the routing table but this does not prevent the route to
be advertised to the other peer!
From the Cisco website:
"You can configure a summary aggregate address for a specified interface. If there are any
more specific routes in the routing table, EIGRP will advertise the summary address out the
interface with a metric equal to the minimum of all more specific routes"
And don't forget YOU HAVE a directly connected route 192.168.1/24 in R1 and .4/24 in R2.
Then your summary is advertised, and the packet loop between R1 and R2.
If you do the test with GNS3, you will see via "show ip eigrp topology" that you FD of your
local subnet 192.168.1.0/24 in R1 become the metric of the summary route
"192.168.0.0/22 advertise to R2 ! And viceversa. Numerically, an administrative distance is
an integer from 0 to 255. In general, the higher the value, the lower the trust rating. An administrative distance of 255 means that the routing information source cannot be trusted at all and should be ignored. http://www.cisco.com/en/US/docs/ios/12_3/iproute/command/reference/ip2_c1g.html A route with an AD of 255 would never be installed in the RIB. It is much better for the router to forward a packet to null0 following the default route than for the router to find out it has no route to destination, drop the packet and probably to send an ICMP unreachable message back to the source of that packet.
https://supportforums.cisco.com/thread/192416 You should not use the ip summary-address eigrp summarization command to generate the default route (0.0.0.0) from an interface. This causes the creation of an EIGRP summary default route to the null 0 interface with an administrative distance of 5. The low administrative distance of this default route can cause this route to displace default routes learned from other neighbors from the routing table. If the default route learned from the neighbors is displaced by the summary default route, or if the summary route is the only default route present, all traffic destined for the default route will not leave the router, instead, this traffic will be sent to the null 0 interface where it is dropped.
http://www.cisco.com/en/US/docs/ios/12_0/np1/configuration/guide/1ceigrp.html#wp4937
Here are the configurations and CLI output to prove the answer is A.
This is done on IOS 12.4T train of code.
R1 interface Loopback0 ip address 192.168.1.1 255.255.255.0 ! interface FastEthernet0/0 ip address 10.1.2.1 255.255.255.0 ip summary-address eigrp 1 192.168.0.0 255.255.252.0 255 ! router eigrp 1 network 10.0.0.0 network 192.168.1.0 no auto-summary R2
interface Loopback0 ip address 192.168.4.2 255.255.255.0 ! interface FastEthernet0/0 ip address 10.1.2.2 255.255.255.0 ip summary-address eigrp 1 192.168.0.0 255.255.248.0 255 ! router eigrp 1 network 10.0.0.0 network 192.168.4.0 no auto-summary Show Output
Look at R1 s routing table...notice it does NOT have the summary route to null0 for 192.168.0.0/22 because we have disabled it. It does have a summary route to 192.168.0.0/21 from R2 it is receiving... R1#show ip route | b Gateway Gateway of last resort is not set 10.0.0.0/24 is subnetted, 1 subnets C 10.1.2.0 is directly connected, FastEthernet0/0 C 192.168.1.0/24 is directly connected, Loopback0 D 192.168.0.0/21 [90/156160] via 10.1.2.2, 00:03:45, FastEthernet0/0 Now look at R2 s routing table. Notice it does NOT have a summary route to null0 for the 192.168.0.0/21 because we disabled it. It does however have a route for 192.168.0.0/22 received from R1. R2#sh ip route | b Gateway
Gateway of last resort is not set
C 192.168.4.0/24 is directly connected, Loopback0
10.0.0.0/24 is subnetted, 1 subnets
C 10.1.2.0 is directly connected, FastEthernet0/0
D 192.168.0.0/22 [90/156160] via 10.1.2.1, 00:05:36, FastEthernet0/0
Now, what will happen? As I said -- When R1 pings 192.168.3.1 it will look in its routing
table, and it will see the
EIGRP route 192.168.0.0/21 from R2 so it will send the packet to R2 since 192.168.3.1 is
part of that summary.
R2 will get the packet and look in its routing table. It will find an EIGRP route for
192.168.0.0/22 from R1 and route the packet back to R1 since 192.168.3.1 is within that
summary range.
This continues in a loop until the IP TTL expires.
Traceroute from R1. Notice it goes to R2 then right back to R1...Hope this helps! --------------
R1#trace 192.168.3.1 Type escape sequence to abort. Tracing the route to 192.168.3.1
1 10.1.2.2 0 msec 0 msec 4 msec
2 10.1.2.1 0 msec 0 msec 4 msec 3 * * *
NEW QUESTION: 2
A. Option C
B. Option A
C. Option D
D. Option B
Answer: B
Explanation:
Explanation
- Scenario: Database2 will contain a stored procedure named usp_UpdateInventory. Usp_UpdateInventory will manipulate a table that contains a self-join that has an unlimited number of hierarchies.
- A table variable can be very useful to store temporary data and return the data in the table format.
- Example: The following example uses a self-join to find the products that are supplied by more than one vendor. Because this query involves a join of the ProductVendor table with itself, the ProductVendor table appears in two roles. To distinguish these roles, you must give the ProductVendor table two different aliases (pv1 and pv2) in the FROM clause. These aliases are used to qualify the column names in the rest of the query.
This is an example of the self-join Transact-SQL statement:
NEW QUESTION: 3
Review the example below:
Product
All Products
Alternate Product Hierarchy
All Products
High Calorie, Sugar Filled Products
Your target Essbase database requires an alternate of the Product, rolling up product
SKUs by Caffeinated and NonCaffeinated. You currently maintain this value as a property.
Once a valid export is built, what are the two ways you can create the new hierarchy in an existing version?
A. Use the DRM Migration utility to build the alternate hierarchy into an existing version.
B. Use an Import to build the alternate hierarchy in DRM into the existing version.
C. Use an Import to build the alternate hierarchy into a new version and then the Blend feature to blend into an existing version.
D. Use an Action script to build the alternate hierarchy into the existing version.
E. Use the DRM Migration utility to build the alternate hierarchy into a new version and then the Blend feature to blend into an existing version.
Answer: B,C
NEW QUESTION: 4
Which FlexNetwork architecture component provides high performance and low-latency for virtual and physical servers that provide services to the users in a company?
A. FlexFabric
B. FlexArchitecture
C. FlexNet
D. FlexDataCenter
Answer: A
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