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Exam Code: JN0-1103
Exam Name: Design, Associate (JNCIA-Design)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
Which option describes information that must be considered when you apply an access list to a physical
interface?
A. Protocol used for filtering
B. Direction of the access group
C. Direction of the access list
D. Direction of the access class
Answer: B
Explanation:
Explanation
Applying an Access List to an Interface
#interface type number
#ip
access-group {access-list-number | access-list-name} { in | out} Source:
http://www.cisco.com/c/en/us/td/docs/ios-xml/ios/sec_data_acl/configuration/xe-3s/sec-data-acl-xe-3s-
book/sec-create-ip-apply.html

NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT CustNoFROMtblDepositAcctUNION ALL SELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo =L.CustNoWHERE D.CustNo IS NULL
Answer: A
Explanation:
Explanation
Would list the customers with duplicates, which would equal the number of accounts.

NEW QUESTION: 3
HOTSPOT
Your company has an Exchange Server 2016 organization.
You plan to allow several users to access the mailboxes of the other group.
You need to ensure that a user named User1 can read and delete the email messages in the mailbox of a user named User2. User1 must add the mailbox of User2 manually to the Microsoft Outlook profile.
What command should you run? To answer, select the appropriate options in the answer area.
Hot Area:

Answer:
Explanation:

Explanation/Reference:
References:
https://technet.microsoft.com/en-us/library/bb124097(v=exchg.160).aspx?f=255&MSPPError=-
2147217396

NEW QUESTION: 4
After installing HP System Management Homepage (SMH) and restarting the system, how can you log in to the SMH?
A. Open a browser and enter: https://ip-address:2381; then log in to the SMH page.
B. Open a browser and enter: http://ip-address; then log in to the SMH page.
C. Start HP SMH from the system console and log in using your account information.
D. You must log in locally, start SMH, and log in as Administrator.
Answer: A


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