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Exam Code: JN0-682
Exam Name: Data Center, Professional (JNCIP-DC)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
웹 애플리케이션 프런트 엔드는 Elastic Load Balancer 뒤의 여러 EC2 인스턴스로 구성됩니다. 인스턴스가 상태 확인을 통과하지 못한 경우 이러한 EC2 인스턴스에서 상태 확인을 수행하도록 ELB를 구성했습니다.
A. 인스턴스가 ELB로 자동 교체됩니다.
B. 인스턴스가 ELB에 의해 자동으로 종료됩니다.
C. ELB가 상태 확인에 실패한 인스턴스로 트래픽 전송을 중지합니다.
D. 근본 원인 분석을 위해 인스턴스가 ELB에 의해 격리됩니다.
Answer: C

NEW QUESTION: 2
Oracle Solaris 11 limits access to the system with usernames and passwords
The usernames are held in ___________, and the passwords are held in ___________.
Select the correct pair.
A. /etc/security /etc/passwd
B. /etc/shadow /etc/passwd
C. /etc/passwd /etc/shadow
D. /etc/security/policy.conf /etc/passwd
Answer: C
Explanation:
The /etc/passwd file contains basic user attributes. This is an ASCII file that contains an entry for each user. Each entry defines the basic attributes applied to a user.
/etc/shadow file stores actual password in encrypted format for user's account with additional properties related to user password i.e. it stores secure user account information. All fields are separated by a colon (:) symbol. It contains one entry per line for each user listed in /etc/passwd file.

NEW QUESTION: 3
어떤 품질 도구가 계약 내에서 허용되는 상한 및 하한 한도를 포함합니까?
A. 체크 시트
B. 관리도
C. 파레토 다이어그램
D. 순서도
Answer: B

NEW QUESTION: 4
You have an Azure Cosmos DB database that uses the SQL API. The database contains a collection named People. People contains SON documents that describe the relationships between individual people and their fends.
The following is a sample of the JSON document.

You need to create a SQL query that retrieves the names of Karen Archer's friend. The results must be formatted as shown in the following output.

Which SQL query should you use?
A. SELECT VALUE friend.name FROM people JOIN friend IN people. Friends. WIERE people-name = "Karen Archer"
B. SELECT friend FROM people JOIN friend IN people. Friends. WIERE people-name = "Karen Archer"
C. SELECT friend FROM people JOIN friend IN people. Friends. WIERE people-name = "Karen Archer"
D. SELECT VALUE friend FROM people JOIN friend IN people. Friends. WIERE people-name = "Karen Archer"
Answer: A


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